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UPSC Prelims

Mathematics

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Elementary Algebra / प्रारंभिक बीजगणित

Q60 2021, Elementary Algebra

Consider the following multiplication problem: (PQ) x 3 = RQQ, where P, Q and R are different digits and R ≠ 0. What is the value of (P+R) ÷ Q?

निम्नलिखित गुणन (मल्टिप्लिकेशन) के प्रश्न पर विचार कीजिए : (PQ) × 3 = RQQ, जहाँ P, Q और R भिन्न अंक हैं और R≠0 है। (P+R) + Q का मान क्या है ?

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Here if we take Q = 5 only then after multiplication by 3 the units place will also be 5.

P5 × 3 = R55

Again, putting P = 8 we get 85 × 3 = 255 ⇒ R = 2, P = 8, Q = 5.

For any other value of P i.e. less than 8 overall multiplication value does not have 55 at the end.

Hence (P+R) /Q = (8 + 2)/ 5 = 2.

Hence, option 2 is correct.

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