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CSAT 2020

Q8 2020, CSAT 2020

• XYZ is a three-digit number.

• So, we can write this as: 100X + 10Y + Z (as X is at hundreds place and Y is at tens place)

• So, XYZ + YZX + ZXY = (100X + 10Y + Z) + (100Y + 10Z + X) + (100Z + 10X + Y) = 111 (X + Y + Z)

• Hence, it is divisible by (X + Y + Z).

• 111 is divisible by 3, as well as 37.

• So, the expression XYZ + YZX + ZXY is not divisible by 9.

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