Option D: Between 7:05 hours and 7:10 hours
To determine when the hour and minute hands of a clock make an angle of 180°, we need to calculate the positions of the hands at different times.
     ● Step 1: Calculate the angle moved by the hour hand.  
           ○ The hour hand moves 360° in 12 hours, which is 30° per hour.
           ○ At 7:00, the hour hand is at 7 × 30° = 210°.
     ● Step 2: Calculate the angle moved by the minute hand.  
           ○ The minute hand moves 360° in 60 minutes, which is 6° per minute.
           ○ At 7:00, the minute hand is at 0°.
     ● Step 3: Determine the time when the angle between the hour and minute hands is 180°.  
           ○ Let the time be 7:x minutes.
           ○ The angle of the hour hand at 7:x is 210° + 0.5x° (since it moves 0.5° per minute).
           ○ The angle of the minute hand at 7:x is 6x°.
           ○ We need the absolute difference between these angles to be 180°:
         $$|(210 + 0.5x) - 6x| = 180$$
         $$|210 - 5.5x| = 180$$
     ● Step 4: Solve the equation.  
           ○ Case 1: $210 - 5.5x = 180$
         $$210 - 5.5x = 180 \implies 5.5x = 30 \implies x = \frac{30}{5.5} \approx 5.45$$
           ○ Case 2: $5.5x - 210 = 180$ (not possible as it would imply a negative x)
     ● Conclusion: The hands make an angle of 180° at approximately 7:05.45, which is between 7:05 and 7:10.  
     Therefore, the correct answer is Option D: Between 7:05 hours and 7:10 hours.